x^2+14x-127.4=0

Solution for x^2+14x-127.4=0 equation:

x^2+14x-127.4=0

a = 1; b = 14; c = -127.4;
Δ = b2-4ac
Δ = 142-4·1·(-127.4)
Δ = 705.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-\sqrt{705.6}}{2*1}=\frac{-14-\sqrt{705.6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+\sqrt{705.6}}{2*1}=\frac{-14+\sqrt{705.6}}{2}
$